[Mukade]

ln (tan x + sec x) +C, lol, ez

[mGGPrometheus]

Originally Posted by pinealan

lnlsecx+tanxl + C
thats an identity in my textbook which I am supposed to memorize =P

Yep, although I never thought that was the obvious solution. An alternative solution is to multiply the top and bottom by cos(x) and use the substitution u = sin(x).

[AxS.pinealan]

Well, my solution is to multiply the top and botton by (secx+tanx)

[FlashVeno]

3+100÷5(2)

is brackets the same as times? if it is then its 43
but if you follow bodmas brackets are first, so its 13
wolfram alpha says 43..what do you guys think?

[|Erasmus|]

you evaluate the (2) first, not the 5 x 2 cause that's not what's in brackets.

wolfram alpha is 100% correct.

Quick Comments

mGGAequitas:

wolframalpha is always correct :)

[TheGentleman]

I thought I'd do this graphically for you cause it looks better ^^



I find it's best to look at the equation written in fractions like so:



Because it can also be written like so:



At this point in time it's up to you how you solve the equation. You can either multiply the Numerator of each fraction and Denominator of each fraction by each other to get this:



OR you can resolve each fraction first and then multiply the numbers left behind by each other like so:



Either way the answer is the same. The important thing to note is that 100 is the numerator and 5 is the denominator of fraction one while 2 is a fraction on its own. 5 * 2 is multiplying the denominator of one fraction by the numerator of the other and is the reason why 13 is not the correct answer.

i.e. is the problem.

I hoped this helps

+ [old content... now irrelevance] +

3+100÷5(2)

expands to look like this:

3 + ((100 / 5) * 2)
= 3 + (20 * 2)
= 43

OR

3 + ((100 * 2) / 5)
= 3 + (200 / 5)
= 43

in short yes... brackets indicate multiplication unless otherwise specified.

Edit:

Originally Posted by |Erasmus|

you evaluate the (2) first, not the 5 x 2 cause that's not what's in brackets.

Actually... the 2 is in brackets on its own so technically the stuff within the brackets is already resolved and it just indicates multiplication. Then it's simple BOMDAS... considering Multiplication and Division are considered equal it doesn't matter whether you perform 100 / 5 first or 100 * 2 first... just as long as you don't do 5 * 2 because 5 is a denominator not a numerator.

P.S. I read eras' message wrong confusing me ^^ still all information is good information.

[|Erasmus|]

yeah... that's what i said... it's just (2) inside the brackets, so only the 2 is evaluated by bomdas. so you don't do 5x2. which gives the alternative (wrong) answer 13

Quick Comments

TheGentleman:

ah right... nvm... I just tripped over the terminology that was used <.< My bad.

[FlashVeno]

thanks now i know xD
i thought it was 13 before lol

[syfPhoenix]

So much of the stuff in this thread has gone over my head... :S im screwed when i get back to school T_T

Quick Comments

eCKo`Tazerenix:

Most of it is uni level anyway

[AxS.pinealan]

Was working on some public exam past papers when I stumbled upon this:
Intergrate

I have no idea how to do this T.T

Edit: thx for telling me that link didnt work, i'll just write it here
Int sec^5(x) dx

Quick Comments

	|Erasmus|:	link no work for me...
	mGGPrometheus:	^
	Mukade:	Not for me either. You know how much I love doing your maths problems for you :P

[mGGPrometheus]

Originally Posted by pinealan

Was working on some public exam past papers when I stumbled upon this:
Intergrate

I have no idea how to do this T.T

Edit: thx for telling me that link didnt work, i'll just write it here
Int sec^5(x) dx

As in the previous problem, you can multiply the top and bottom by the same factor:

The result follows by u-substitution.

[ToRSpartaz]

Reading some of these calc equations makes me just want to study again >< not a good sign O_o

Quick Comments

FaDeBadger:

This, loved it in High school

[AxS.pinealan]

er, I still cant work out the answer... do I have to use integration by part?
What I now have is
Not sure if it is correct. May I ask for a bit more help?

[Mukade]

That's a really hard problem pinealan. I think you have to use the reduction formula for sec^n (x), no idea what it is though, sorry.

[Mukade]

http://en.wikipedia.org/wiki/Integral_of_secant_cubed That should have them!

[faithHunter]

Kinda off topic but can someone explain to me what exactly is a Tesseract? The youtube videos I watched said that its a "cube inside of a cube" but when you rotate it it gets really really weird and incomprehensible IMHO.

[AxS.pinealan]

the thing i hate about integration is that there are tons of possible representations of the answer, and I have no clue if mine is a correct one.
Another answer that I just worked out with Mukade's help:

Quick Comments

Zepph:

Is that your handwriting? It's so ridiculously neat I could eat it.

[Delraich]

Something I found recently that might be interesting for you to solve (cipher codes). The solutions are on the web, so if you want a challenge don't Google the answer. Try and solve them in less than 44 hours without cheating

I will start with the easiest to the hardest:

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6.
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7.
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8a.
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8b.
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Quick Comments

Zepph:

Challenge accepted!

[AxS.pinealan]

Originally Posted by Delraich

Something I found recently that might be interesting for you to solve (cipher codes). The solutions are on the web, so if you want a challenge don't Google the answer. Try and solve them in less than 44 hours without cheating

One hour passed, decoded the first three, lets see if I can get the rest.

[AxS.pinealan]

Originally Posted by pinealan

*Zepph: *
Is that your handwriting? It's so ridiculously neat I could eat it.

Sorry for the double post, but yes, thats my handwriting. Well I took my time to make it as neat as possible