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Unread Wed, 9th-Jan-2013, 3:15 AM BnetId: faithHunter 598  Race: Clan: TN  Location: Indonesia  Total Posts Made: 260 # 21
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I now realize how mathemathically less inclined I am compared to the rest of you guys now after reading through this thread.

I don't even get half the terms that you are using :P

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 mGGNemesis:  
lol poor faith; dw :)
 RVLiveR:  
it's okay, everything is equal to 1 if 1+1=1
 AxS.Sorathez:  
If 1+1=1 then anything and everything is true :D
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Unread Wed, 9th-Jan-2013, 4:09 AM BnetId: pinealan.998  Race: Clan: AxS  Location: Hong Kong  Total Posts Made: 151 # 22
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Hey I got a trigonometry question for you guys:
Use mathematical induction to prove that for any positive integer n,
sinx+sin3x+...+sin(2n-1)x= (1-cos2nx)/2sinx
where sinx =/= 0
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Unread Wed, 9th-Jan-2013, 8:00 AM BnetId: cTmukade.551  Race: Location: Canberra, Australia  Total Posts Made: 152 # 23
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Quote:
Originally Posted by pinealan View Post
Hey I got a trigonometry question for you guys:
Use mathematical induction to prove that for any positive integer n,
sin x+sin 3x+...+sin(2n-1)x= (1-cos2nx)/2sin x
where sin x =/= 0
I'll use the indentity (1) (sin x)^2= (1-cos 2x)/2
because (sin nx)^2/(sin x) is easier to work with.
and also use
(2) (sin A sin B=1/2(cos(A-B)-cos(A+B))


Set n=1

lhs=sinx
rhs=(sin x)^2/sin x
=sin x
=lhs
true for n=1

Assume n=k
sin x+ sin 3x+...+sin(2k-1)x=(sin kx)^2/(sin x)

For n=k+1

lhs= ((sin kx)^2)/sin x+sin(2k+1)x
=(((sin kx)^2)+sin(2k+1)x sin x)/sin x
=(((sin kx)^2)+1/2(cos(x-2kx-x)-cos(2kx+2x))/sin x (2)
=(((sin kx)^2)+1/2(cos(-2kx)-cos(2kx+2x))/sin x
=(((sin kx)^2)+1/2(cos(2kx)-cos(2kx+2x))/sin x
=((((sin kx)^2)+1/2(1-2(sin kx)^2-(1-2(sinkx+x))^2))/sin x
=((((sin kx)^2)+1/2(2(sin kx+x))^2-2(sin kx)^2))/sin x
=((sin kx)^2+(sin kx+x))^2-(sin kx)^2)/sin x
=(sin(k+1)x)/sin x
=rhs

Therefore, true for all n.
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Unread Wed, 9th-Jan-2013, 8:01 AM BnetId: cTmukade.551  Race: Location: Canberra, Australia  Total Posts Made: 152 # 24
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Admittedly, I've done this question before and still have the textbook worked solution >.>

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 syfPhoenix:  
Knew it was too good to be true. :P
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Unread Wed, 9th-Jan-2013, 8:17 AM Race: Clan: AUX  Total Posts Made: 158 # 25
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I don't want to live on this planet any more.

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 Mukade:  
Lololol
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lolol
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Unread Wed, 9th-Jan-2013, 8:33 AM Who's Who:   BnetId: ToRErasmus.733  Race: Clan: ToR  Location: Sydney  Total Posts Made: 1,454 # 26
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 Mukade:  
This is amazing
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Unread Wed, 9th-Jan-2013, 9:53 AM BnetId: Zepph.293  Race: Location: Unkown  Total Posts Made: 258 # 27
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I could fap to this thread.

Maths .

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NERD
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@Maynerd: And don't you forget it!!
 RVLiveR:  
zepph is my new best friend~ ^.^
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Unread Wed, 9th-Jan-2013, 12:57 PM Who's Who:   BnetId: TheGentleman.565  Race: Clan: ToR  Location: Brisbane, Australia  Total Posts Made: 533 # 28
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I know this probably belongs in the puns thread but... I'm so glad this thread exists.

I wish you were sine^2 and I was cosine^2 so together we could be 1

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 Mukade:  
Cute as bro :P
 AxS.pinealan:  
lol nice pun, never have thought of that before
 AxS.Sorathez:  
I love it :D You can always be my Cos^2
 mGGNemesis:  
awwww nice <3
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Unread Wed, 9th-Jan-2013, 6:32 PM BnetId: pinealan.998  Race: Clan: AxS  Location: Hong Kong  Total Posts Made: 151 # 29
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Well, frankly, I pulled that question from my textbook too :P
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Unread Wed, 9th-Jan-2013, 6:40 PM BnetId: Sorathez.581  BattleTag: Sorathez#2958  Race: Location: Fairfield, Australia  Total Posts Made: 114 # 30
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Quote:
Originally Posted by Mukade View Post
I'll use the indentity (1) (sin x)^2= (1-cos 2x)/2
because (sin nx)^2/(sin x) is easier to work with.
and also use
(2) (sin A sin B=1/2(cos(A-B)-cos(A+B))


Set n=1

lhs=sinx
rhs=(sin x)^2/sin x
=sin x
=lhs
true for n=1

Assume n=k
sin x+ sin 3x+...+sin(2k-1)x=(sin kx)^2/(sin x)

For n=k+1

lhs= ((sin kx)^2)/sin x+sin(2k+1)x
=(((sin kx)^2)+sin(2k+1)x sin x)/sin x
=(((sin kx)^2)+1/2(cos(x-2kx-x)-cos(2kx+2x))/sin x (2)
=(((sin kx)^2)+1/2(cos(-2kx)-cos(2kx+2x))/sin x
=(((sin kx)^2)+1/2(cos(2kx)-cos(2kx+2x))/sin x
=((((sin kx)^2)+1/2(1-2(sin kx)^2-(1-2(sinkx+x))^2))/sin x
=((((sin kx)^2)+1/2(2(sin kx+x))^2-2(sin kx)^2))/sin x
=((sin kx)^2+(sin kx+x))^2-(sin kx)^2)/sin x
=(sin(k+1)x)/sin x
=rhs

Therefore, true for all n.
I had quite the love/hate relationship with mathematical induction in High School...
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Unread Wed, 9th-Jan-2013, 8:57 PM Who's Who:   BnetId: TheGentleman.565  Race: Clan: ToR  Location: Brisbane, Australia  Total Posts Made: 533 # 31
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Quote:
Originally Posted by pinealan View Post
Well, frankly, I pulled that question from my textbook too :P
Now now... we won't do your homework for you!
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Unread Wed, 9th-Jan-2013, 9:55 PM Who's Who:   BnetId: ToRErasmus.733  Race: Clan: ToR  Location: Sydney  Total Posts Made: 1,454 # 32
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And here's what we all want math to be:
+ Show +
Click the image to open in full size.


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 ToRSpartaz:  
MAAAAAAAAAAAAAAAATH
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Unread Fri, 11th-Jan-2013, 5:22 AM BnetId: Spook.389  Race: Clan: ToR  Location: Adelaide, Australia  Total Posts Made: 1,570 # 33
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[6:50:21 AM] Nick "ToRSpartaz" Simpson: 10 + - 11 is 21

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 Mukade:  
Pure genius
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Unread Fri, 11th-Jan-2013, 6:02 AM Who's Who:   BnetId: Spartaz. 780  Race: Clan: ToR  Location: Auckland, New Zealand  Total Posts Made: 2,184 # 34
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In my defense, I only woke up a few minutes before that comment...

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 mGGNemesis:  
lolol
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Unread Fri, 11th-Jan-2013, 6:06 AM Who's Who:   BnetId: mGGNemesis. 653  BattleTag: 14350  Race: Clan: mGG  Location: Singapore  Total Posts Made: 1,822 # 35
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I this thread

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 Mukade:  
:)
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"and we'll invest more on Bots, as our first Trial bot, the 'NemBotElie' was a huge success, organising tournaments and being part of the Council of mGG. But there are a few bugs in which the bot cannot go past the skill level of a Platinum Protoss." - PaRAnorMaL
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Unread Fri, 11th-Jan-2013, 6:09 AM Who's Who:   BnetId: Spartaz. 780  Race: Clan: ToR  Location: Auckland, New Zealand  Total Posts Made: 2,184 # 36
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Love Math, hate proofs T_T, proofs make me die a little inside

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 ToRLuneth:  
So does basic arithmetic it seems <3
 ToRSmotPokingFish:  
this^^
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Unread Fri, 11th-Jan-2013, 7:49 AM BnetId: arteezy  Race: Location: Singapore  Total Posts Made: 622 # 37
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Wait, so i can scan sheets of my homework in, and people will just answer it yeh? ^.^
I approve of this thread

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 |Erasmus|:  
no.
 ToRsupapower:  
no.
 Mukade:  
I might. I promise I won't answer them wrong
 mGGPrometheus:  
I probably would
 RVLiveR:  
mm koreans asking for help at math..
 mGGNemesis:  
anyone could... though I'm not sure about trusting the answers ;)
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Unread Fri, 11th-Jan-2013, 7:14 PM BnetId: sRLiveR.539  Race: Clan: sR  Location: Jakarta, Indonesia  Total Posts Made: 219 # 38
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yo guys for anybody who will be at the coming SEAMC you should greet me ^.^ I'll be in the JIS A-Team with two koreans so I'll stand out :P
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Unread Sat, 12th-Jan-2013, 7:45 PM BnetId: arteezy  Race: Location: Singapore  Total Posts Made: 622 # 39
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Quote:
Originally Posted by Antelopes View Post
*sRLiveR: *
mm koreans asking for help at math..
Wow, that stereotype T_T.
I'm Wood League in Math ;_;
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Unread Sat, 12th-Jan-2013, 8:11 PM BnetId: pinealan.998  Race: Clan: AxS  Location: Hong Kong  Total Posts Made: 151 # 40
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Quote:
Originally Posted by Antelopes View Post
Wow, that stereotype T_T.
I'm Wood League in Math ;_;
You mean Korean wood league? Thats NA Masters

Quick Comments
 Mukade:  
Lolololol
 syfPhoenix:  
I lol'd a little.
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